1.

Volume occupied by one molecule of water (density = 1 g `cm^(3)`)A. `3.0xx10^(-23) cm^(3)`B. `5.5xx10^(-23)cm^(3)`C. `9.0xx10^(-23)cm^(3)`D. `6.023xx10^(-23)cm^(3)`

Answer» Correct Answer - A
Mass of 1 molecule of water
`=(18)/(6.022xx10^(23))=3xx10^(-23)g`.
Density of water = 1.00 g `cm^(-3)`
`:.` volume occupied by one molecule of water
`=3xx10^(-23)cm^(-3)`


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