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Volume occupied by one molecule of water (density = 1 g `cm^(3)`)A. `3.0xx10^(-23) cm^(3)`B. `5.5xx10^(-23)cm^(3)`C. `9.0xx10^(-23)cm^(3)`D. `6.023xx10^(-23)cm^(3)` |
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Answer» Correct Answer - A Mass of 1 molecule of water `=(18)/(6.022xx10^(23))=3xx10^(-23)g`. Density of water = 1.00 g `cm^(-3)` `:.` volume occupied by one molecule of water `=3xx10^(-23)cm^(-3)` |
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