1.

Volume occupied by single CsCl ion pair in a crystal is 7.014 xx 10^(-23) c^(3). The smallest Cs-Csinternuclear distance is equal to length of the side of the cube corresponding to volume of one CsCl ion pair. The smallest Cs to Cs internuclear distance is nearly

Answer»

4.4Å
4.3Å
4Å
4.5 Å

Solution :Volume of `CsCl=a^(3)`
`7.014xx10^(-23)CM^(3)=a^(3)` ( a = edge LENGTH)
`a= root3(7.014xx10^(-23))`
`a=4.12xx10^(-8)cm=4.12 Å ~~4Å`


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