1.

Volume of 0.1 M H_(2)SO_(4) required to neutralize 30 ml of 0.2 N NaOH is

Answer»

30 ml
15 ml
40 ml
60 ml

Solution :`0.1M" of "H_(2)SO_(4) implies0.2N" of "H_(2)SO_(4)`
`thereforeN_(1)V_(1)=N_(2)V_(2)`[N=2M for `H_(2)SO_(4)`]
`0.2xxV_(1)=0.2xx30`
`thereforeV_(1)=30ML`


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