1.

Volume of 0.1 M K_(2)Cr_(2)O_(7) required to oxidise 35 mL of 0.5 M Fe SO_(4) solution is

Answer»

29.2 mL
17.5 mL
175 mL
145 mL

Solution :`(({:(K_(2)Cr_(2)O_(7)+4H_(2)SO_(4)toK_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+4H_(2)O+3[0]),(2FeSO_(4)+H_(2)SO_(4)+[O]toFe_(2)(SO_(4))_(3)+H_(2)Oxx3):})/(K_(2)Cr_(2)O_(7)+7H_(2)SO_(4)+6FeSO_(4)toK_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+7H_(2)O+3Fe_(2)(SO_(4))_(3)))/`
`(M_(1)V_(1))/(n_(1) = (M_(2)V_(2))/(n_(2))`
`(K_(2)Cr_(2)O_(7) = (FeSO_(4))`
`(0.1xxV_(1))/(1)=(0.5xx35)/(6xx0.1)`
`V_(1) = (0.5xx35)/(6xx0.1)=29.2 mL`


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