1.

Volume of a gas at STP is 1.12 xx 10^(-7) cm^3.The number of molecules present in it is

Answer»

`3.01 xx 10^8`
`3.01 xx 10^22`
`3.01 xx 10^11`
`3.01 xx 10^12`

SOLUTION :`22400 cm^3` of the gas at STP has molecules ` = 6.02 xx 10^23`
`1.12 xx 10^(-8) cm^3` of the gas at STP will have molecules
` = (6.02 xx 10^23)/(2400) xx 1.12 xx 10^(-8)`
` = 3.01 xx 10^11 ` molecules


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