Volume of a room is 15 m times 12 m times 8m. The room was at 22^@C in the morning.What is the percentage of initial volume of air of the room that is expelled when the room temperature reaches 30^@C at noon? The pressure remains constant during the change of temperature.

Volume of a room is 15 m times 12 m times 8m. The room was at 22^@C in

1.	Volume of a room is 15 m times 12 m times 8m. The room was at 22^@C in the morning.What is the percentage of initial volume of air of the room that is expelled when the room temperature reaches 30^@C at noon? The pressure remains constant during the change of temperature.
Answer» Solution :From Charle.s LAW , `V_1/T_1=V_2/T_2` or `V_1/V_2=T_1/T_2` or,`V_1/(V_2-V_1)=T_1/(T_2-T_1)or,(V_2-V_1)/V_1times100=(T_2-T_1)/T_1times100` Given, `T_1=22^@C=295 K,T_2=30^@C=303 K,V_2-V_1`=volume of EXPELLED air `THEREFORE(V_2-V_1)/V_1times100=(T_2-T_1)/T_1times100=(303-295)/295times100=2.7` `therefore 2.7%` of air will be expelled from the room.