Volume strength of resulting solution = 1.339 × 5.6 = 7.5 the degree

1.	Volume strength of resulting solution = 1.339 × 5.6 = 7.5 the degree of hardness of a given sample of hard water is 60 ppm. If the entire hardness is due to MgSO4, how much of MgSO4 is present per kilogram of hard water?
Answer» Degree of hardness of water = 60ppm Since degree of hardness is the number of parts of calcium carbonate or equivalent to calcium and magnesium salts present in a million parts of water by mass. 10⁶ g of water contain 60 g of CaCO₃ Now 1 mol of CaCCO₃ = 1 mol of MgSO₄ 100g of CaCOa = 120g of MgSO₄ 10⁶ g of water contain MgSO₄ = \(\frac{60\times 200}{100}\) = 72 g 10³ g of water will contain MgSO4 = \(\frac{72}{10^6}\) x 10³ = 0.072 g 1 kg of water contain MgSO₄ = 72 mg

Volume strength of resulting solution = 1.339 × 5.6 = 7.5 the degree of hardness of a given sample of hard water is 60 ppm. If the entire hardness is due to MgSO4, how much of MgSO4 is present per kilogram of hard water?

Answer»

Degree of hardness of water = 60ppm

Since degree of hardness is the number of parts of calcium carbonate or equivalent to calcium and magnesium salts present in a million parts of water by mass.

10⁶ g of water contain 60 g of CaCO₃

Now 1 mol of CaCCO₃ = 1 mol of MgSO₄

100g of CaCOa = 120g of MgSO₄

10⁶ g of water contain MgSO₄ = \(\frac{60\times 200}{100}\) = 72 g

10³ g of water will contain MgSO4 = \(\frac{72}{10^6}\) x 10³ = 0.072 g

1 kg of water contain MgSO₄ = 72 mg

Discussion

No Comment Found

Related InterviewSolutions

When temporary hard water containing `Mg(HCO_(3))_(2)` is boiled, the ppt. formed is ofA. `MgCO_(3)`B. `MgO`C. `Mg(OH)_(2)`D. None of these
Water is said to be permanently hard when it contains `:`A. Chloride and sulphates of `Mg` and `Ca`B. Bicarbonates of `Na` and `K`.C. Carbonates of `Na` and `K`D. Phosphate of `Na` and `K.`
Hydrogen gas is not liberated when the following metal is added to dil. `HCl :`A. `Mg`B. `Sn`C. `Ag`D. `Zn`
When zeolite, which is hydrated sodium aluminium silicate, is treated with hard water, the sodium ions are are exchanged withA. `H^(+) ion`B. `Ca^(2+) ion`C. `SO_(4)^(2-) ion`D. `HO^(-) ion`
When zeolite, which is hydrated sodium aluminium silicate is treated with hard water, the sodium ions `(Na^(o+))` are exchanged withA. `OH^(-)` ionsB. `SO_(4)^(2-)`ionsC. `Ca^(2+)` ionsD. `H^(+)` ions
When zeolite, which is hydrated sodium aluminate silicate, is treated with hard water, the sodium ions are exchanged with:A. `Cl^(ɵ)`B. `SO_(4)^(ɵ)`C. `Ca^(2+)`D. `Mg^(2+)`
When zeolite, which is hydrated sodium aluminium silicate is treated with hard water, the sodium ions `(Na^(o+))` are exchanged withA. `H^(o+)` ionsB. `Ca^(2+)` ionsC. `SO_(4)^(2-)` ionsD. `overset(Theta)(O)H` ions
When zeolite, which is hydrated sodium aluminium silicate, is treated with hard water, the sodium ions are exchanged withA. `H^(+)`B. `Ca^(+2)`C. `OH`D. `SO_(4)^(2-)`
One mole of calciium phosphide on reaction with excess water givesA. One mole of phospheneB. Two moles of phospheneC. Two moles of phospheneD. One mole of phosphene pentoxide
When zeolite, which is hydrated sodium aluminate silicate, is treated with hard water, the sodium ions are exchanged with:A. `H^(+)`ionsB. `Ca^(2+)` ionsC. `Mg^(2+)` ionsD. Both `Ca^(2+)` and `Mg^(2+)`

Volume strength of resulting solution = 1.339 × 5.6 = 7.5 the degree of hardness of a given sample of hard water is 60 ppm. If the entire hardness is due to MgSO4, how much of MgSO4 is present per kilogram of hard water?

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment