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Volume V_1 ml of 0.1 K_(2) Cr_(2) O_(7) is needed for complete oxidation of 0.67g N_(2)H_4 in acidic medium The volume of 0.3 M KMnO_4 need for same oxidation state in acidic medium will be |
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Answer» `2/5 V_(1)` `V_(1) XX 0.1 xx 6 = V_2 xx0.3 xx 5` Vol. of `KMnO_4 ,V_(2)=2/5 V_1` |
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