1.

Volume V_1 ml of 0.1 K_(2) Cr_(2) O_(7) is needed for complete oxidation of 0.67g N_(2)H_4 in acidic medium The volume of 0.3 M KMnO_4 need for same oxidation state in acidic medium will be

Answer»

`2/5 V_(1)`
`5/2 V_1`
`113V_1`
can.t say

Solution :`V_(1)M_1 xxn_1 ` (n - factor) `= V_(2) M_2 xxn_2`
`V_(1) XX 0.1 xx 6 = V_2 xx0.3 xx 5`
Vol. of `KMnO_4 ,V_(2)=2/5 V_1`


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