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व्यंजक : `root(4)(3x+1)=2` में `x` का मान ज्ञात करें।A. 3B. 6C. 4D. 5 |
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Answer» Correct Answer - D `root(4)((3x+1))=2` `(root(4)((3x+1)))^(4)=2^(4)` `(3x+1)^(4xx1/4)=16` `=3x=15, x=5` |
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