InterviewSolution
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InterviewSolution
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(w)(4-k) x2 + (2k + 4) x + (8k +1)=0 |
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Answer» The given quadratic will be a perfect square if it has two real and equal roots. To have two real and equal roots the discriminant must be zero.i.e., b²-4ac=0or, (2k+4)²-4(4-k)(8k+1)=0or, 4k²+16k+16-4(32k-8k²+4-k)=0o², 4k²+16k+16-128k+32k²-16+4k=0or, 36k²-108k=0or, 36k(k-3)=0either 36k=0or, k=0or, k-3=0or, k=3∴, k=0,3 Ans. answer is ❌ wrong |
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