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Walking 4 kmph a student reaches his college 5 minutes late and if he walks at 5 kmph he reaches 2(1/2) minutes early. What is the distance from his house to the college? |
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Answer» Let required distance = x kms At 4 kmph, time taken = X/4 At 5 kmph, time taken = X/5 Given X/4 = 5/60 = X/5 + 25/60s Getting x = 2.5 km |
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