walking at 50% more than his uncal speee..a man reaches his office an

1.	walking at 50% more than his uncal speee..a man reaches his office an hour earlies.How long does he usually take to reachhis ffice,
Answer» take answer Let original speed = sLet original time taken to reach office = t Distance travelled by man = d Then,At original speed s time taken to reach office = d/s For 50% more than original speed time taken to reach office = d/s(1 + 1/2) = 2d/3s As per given condition d/s - 2d/3s = 1(3d - 2d)/3s = 1d = 3s Therefore, Usually time taken to reach office = d/s = 3s/s = 3 hours

walking at 50% more than his uncal speee..a man reaches his office an hour earlies.How long does he usually take to reachhis ffice,

Answer»

take answer

Let original speed = sLet original time taken to reach office = t

Distance travelled by man = d

Then,At original speed s time taken to reach office = d/s

For 50% more than original speed time taken to reach office = d/s(1 + 1/2) = 2d/3s

As per given condition d/s - 2d/3s = 1(3d - 2d)/3s = 1d = 3s

Therefore, Usually time taken to reach office = d/s = 3s/s = 3 hours