Water and chlorobenzene are immiscible liquids.Their mixture boils at 90^@C under a reduced pressure of 7.82 xx 10^4 Pa. The vapour pressure of pure water at 90^@C is 7.03 xx 10^4 Pa. On weight per cent basis, chlorobenzene in the distillate is equal to (mol. wt. of chlorobenzene is 112.5 g "mol"^(-1))

Water and chlorobenzene are immiscible liquids.Their mixture boils at

1.	Water and chlorobenzene are immiscible liquids.Their mixture boils at 90^@C under a reduced pressure of 7.82 xx 10^4 Pa. The vapour pressure of pure water at 90^@C is 7.03 xx 10^4 Pa. On weight per cent basis, chlorobenzene in the distillate is equal to (mol. wt. of chlorobenzene is 112.5 g "mol"^(-1))
Answer» 50 60 70 80 Solution :`p_"MIX"=7.82xx10^4` PA `p_(H_2O) + p_(C_6H_5Cl)=7.82xx10^4` Pa `p_(H_2O) = 7.03xx10^4` Pa `therefore p_(C_6H_5Cl)=0.79xx10^4` Pa `p prop n prop w/m , therefore (w_(C_6H_5Cl)xxM_(H_2O))/(w_(H_2O)xxM_(C_6H_5Cl))=p_(C_6H_5Cl)/p_(H_2O)` `w_(C_6H_5Cl)/w_(H_2O)=(p_(C_6H_5Cl)xxM_(C_6H_5Cl))/(p_(H_2O)xxM_(H_2O))=((0.79xx10^4)xx112.5)/((7.03xx10^4)xx18)`=0.70 Weight per CENT of chlorobenzene is distillate `=0.70xx100` = 70