Water drops fall at regular intervals form a hole at the bottom of a vessel placed at a high level. The ninth drop is about to fall when the first drop just falls on the floor after being in the air for 2 second. The distance between the 3rd and the 5 th drop at the instant is : (Taking g = 10 m//s^(2))

Water drops fall at regular intervals form a hole at the bottom of a v

1.	Water drops fall at regular intervals form a hole at the bottom of a vessel placed at a high level. The ninth drop is about to fall when the first drop just falls on the floor after being in the air for 2 second. The distance between the 3rd and the 5 th drop at the instant is : (Taking g = 10 m//s^(2))
Answer» `(40)/(9) m` `(25)/(4) m` `5 m` `(5)/(16) m` Solution :`H = (1)/(2) xx 10 xx (2)^(2)` `H = 20 m` Time interval between two drops `= (2)/(8) = (1)/(2) sec`. Let the distance TRAVELLED by 3 rd drops is `s_(3) = (1)/(2) xx g xx (1.5)^(2)` Distance travelled by 5th drops `s_(5) = (1)/(2) xx g (1)^(2)` `Delta s = s_(3) - s_(5)`