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Water ejects with a speed of 0.2 ms-1 through a pipe of area of cross-section 1 × 10-2 m2. If the water strikes a wall normally, calculate the force on the wall in newtons, assuming the velocity of the water normal to the wall is zero after the collision. |
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Answer» Volume of water striking the wall per second = 0.2 × 10-2 = 2 × 10-3 m3 Mass of the water striking the wall in one second = volume × density = 2 × 10-3 × 1000 = 2 kg Change in velocity of water on striking the wall in one second = 0.2 – 0 = 0.2 ms-1 Force acting on the wall = change in momentum = 2 × 0.2 = 0.4N. |
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