Water falling from a 50 m high fall is to be used for generating electric enegy. If 1.8xx10^5kg of water falls per hour and half the gravitational potential energyh can be converted into electric energy, how many 100 W lamps can be it?

Water falling from a 50 m high fall is to be used for generating elect

1.	Water falling from a 50 m high fall is to be used for generating electric enegy. If 1.8xx10^5kg of water falls per hour and half the gravitational potential energyh can be converted into electric energy, how many 100 W lamps can be it?
Answer» SOLUTION :`h=50m, m=1.8x10^5kg` `P=100 watt` P.E=mgh` `=1.8xx10^5xx9.8xx50` `=882xx10^5J` Because HALF the potetnial energy is CONVERTED into electricital energy. Electircal energy `=1/2P.E. =441xx10^5J/hr` So, POWER in watt(J/sec)`=(441xx10^5)` `:.` Number of 100 W lamps, that can be lit ` (441xx10^5)/(3600xx100)=122.5~~122`