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Water flows at 2.5 km/h through a pipe of radius 3.5 cm into a rectangle tank of length 10 m and breadth 8.8 m. The time (in hours) in which the level of water in the tank will rise by 42 cm is:1. 3.482. 3.243. 3.964. 3.84 |
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Answer» Correct Answer - Option 4 : 3.84 Given: Speed of water flowing through the pipe = 2.5 km/h = 2500 m/h Radius of pipe = 3.5 cm = 0.035 m Length of tank = 10 m Breadth of tank = 8.8 m Height upto which water to be raised in the tank = 42 cm = 0.42m Formula used: (i) Volume flow rate of water = A × V where, A = Cross section area of pipe V = Speed of water (ii) Volume of cuboid tank = l × b × h where, l = length of tank b = breadth of tank h = height of tank (iii) Time taken to fill the tank = (Total volume to be filled inside the tank)/(Volume flow rate of water) Calculation: Volume flow rate of water through pipe = 2500 × π × 0.035 × 0.035 ⇒ 9.62 m3/hr Total volume of water to be filled inside the tank = 10 × 8.8 × 0.42 ⇒ 36.96 m3 Time taken to fill the tank = 36.96/9.62 ⇒ 3.84 hours ∴ The time (in hours) in which the level of water in the tank will rise by 42 cm is 3.84 hours. Mistake point: Don't forget to make all units same. |
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