InterviewSolution
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InterviewSolution
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Water from a tap emerges vertically downwards with an initial spped of `1.0ms^-1`. The cross-sectional area of the tap is `10^-4m^2`. Assume that the pressure is constant throughout the stream of water, and that the flow is steady. The cross-sectional area of the stream 0.15 m below the tap isA. `5.0xx10^(-4) m^(2)`B. `1.0xx10^(-5)m^(2)`C. `5.0xx10^(-5) m^(2)`D. `2.0xx10^(-5) m^(2)` |
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Answer» Correct Answer - C Decrease in potential energy = increase in kinetic energy `therefore" "rhogh=1/2rho(v_(f)^(2)-v_(i)^(2))` `or" "2(10)(0.15)-v_(f)^(2)-(10)^(2)` `or" "v_(f)= 2 ms^(-1)` Now, from continuity equation, `A_(1)v_(1)=A_(2)v_(2)" or "Aprop1/v` Velocity has become two times, Hence, area of cross-section will remain half. |
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