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Water is flowing down from a water tap of diameter 1.12 cm at the rate of 2 L/min. Discuss the type of flow - laminar or turbulent. The coefficient of viscosity of water is 10^(-3) Pas. |
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Answer» Solution :`D=1.12 xx 10^(-2)m` `V=2L"/MIN"=2/(60) xx 10^(-3) m^(3) s^(-1)` As `V=a v_(c)` `v_(c)=V/a =(V)/(pi D^(2)//4)` As REYNOLD Number `=N_(R)=(pDv_(c))/(eta)` `=(pDV)/(eta n D^(2)//4)` `=(4pV)/(eta pi D)` `=(4 xx 1000 xx 2 xx 10^(-3))/(60 xx 10^(-3) xx 3.14 xx 1.12 xx 10^(-2))` `=3791 gt 3000` The flow is turbulent in nature. |
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