Water is flowing in a pipe of radius 1.5 cm with an average velocity of 15 cm s^(-1) . What is the nature flow ? Given coefficient of viscosity of water is 10^(-3) kg m^(-1)s^(-1) and its density is 10^3 kg m^(-3).

Water is flowing in a pipe of radius 1.5 cm with an average velocity o

1.	Water is flowing in a pipe of radius 1.5 cm with an average velocity of 15 cm s^(-1) . What is the nature flow ? Given coefficient of viscosity of water is 10^(-3) kg m^(-1)s^(-1) and its density is 10^3 kg m^(-3).
Answer» SOLUTION :`D = 2 xx 1.5 cm = 3 xx 10^(-2) m` `v = 15 cm s^(-1) = 0.15 MS^(-1)` `eta= 10^(-3) kg m^(-1)s^(-1)` `R_c = (RHO v D)/(eta) = (10^3 xx 0.15 xx 3 xx 10^(-2))/(10^(-3))` `R_c = 4500` As `R_c > 3000`, so the flow is turbulent.