Water is flowing through a horizontal tube of length 0.25 m and radius4xx 10 ^(-4) m under a constant pressure head of 0.2 m of water, at the rate of 5 xx 10 ^(-6) m^(3) per minutre . Calculate the coefficient of visosity of water. Density of water = 1000 kg m^(-3)

Water is flowing through a horizontal tube of length 0.25 m and radius

1.	Water is flowing through a horizontal tube of length 0.25 m and radius4xx 10 ^(-4) m under a constant pressure head of 0.2 m of water, at the rate of 5 xx 10 ^(-6) m^(3) per minutre . Calculate the coefficient of visosity of water. Density of water = 1000 kg m^(-3)
Answer» <html><body><p></p>Solution :` "" l = 0.25 m, r- 4 xx 10 ^(-4) m ` <br/> ` ""P= h rho g =0.2 m " ofwater"= 0.2 xx 10 ^(3)xx 9.<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a> Pa` <br/>Volume ` V = 5 xx 10 ^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)m^(3)` <br/> ` "" t= ` one minute = <a href="https://interviewquestions.tuteehub.com/tag/60s-330048" style="font-weight:bold;" target="_blank" title="Click to know more about 60S">60S</a><br/>` eta = ? ` <br/>` <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> = ( V)/(t)= (pi P r^(4))/( 8 eta l) ` <br/>` eta = ( pi h rho g r^(4) t)/( gl V) ` <br/> `= (3.14 xx 0.2 xx 10 ^(-3)xx 9.8 xx ( 4 xx 10 ^(-4) ) ^(4) xx 60 )/( 8 xx 0.25 xx 5 xx 10 ^(-6)) ` <br/> `= 0 .000945 <a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> s m^(-2)`</body></html>