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Water is flowing with velocity 4ms^(-1) in a cylinder of diameter 8 cm .It is connectedto a pipe with it end tip of diameter 2cm . Calculate the velocity of water at this free end. |
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Answer» `4MS^(-1)` `A_(2)=pir_(2)^(2)=pixx10^(-4)m^(2)` Now USING equation , `A_(1)v_(1)=A_(2)v_(2)` `v_(2)=(A_(1)v_(1))/(A_(2))=(16pixx10^(-4)xx4)/(pixx10^(-4))=64ms^(-1)` Hence the velocity of water at free end is `v_(2)=64ms^(-1)` |
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