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Water is following at the rate of 5 km/hr through a pipe of diameter 14 cm into a rectangular tank which is 50 m long and 44 m wide. Determine the time in which the level of water in the tank will rise by 7 cm. \(\bigg(\text{Take}\,π = \frac{22}{7}\bigg)\) |
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Answer» Rate of flow = 5 km/hr = 5000 m/hour. ⇒ Length of cylinder for water flowing in one hour = 5000 m. Radius = 7 cm = \(\frac{7}{100}\) m. ∴ Volume of water flowing through the pipe per hour = πr2h \(=\frac{22}{7}\times\frac{7}{100}\times\frac{7}{100}\times5000\) m3 = 77 m3. Volume of water to be filled in the rectangular tank = (50 × 44 × 7/100) m3 = 154 m3 ∴ Reqd. time = \(\frac{154}{77}\) = 2 hours. |
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