Water is nowing through a horizontal pipe of varying cross-section. At a certain point where the velocity is 0-24 m/s the pressure of water is 0-010 metre of mercury. What is the pressure at a point where the velocity is 0-48 m/s?

Water is nowing through a horizontal pipe of varying cross-section. At

1.	Water is nowing through a horizontal pipe of varying cross-section. At a certain point where the velocity is 0-24 m/s the pressure of water is 0-010 metre of mercury. What is the pressure at a point where the velocity is 0-48 m/s?
Answer» Solution :For horizontal FLOW. The Bernoulli.s EQUATION is, ` ""(P_1)/(rho)+(1)/(2)v_1^(2)= (P_2)/(rho)+(1)/(2)v_2^(2) ` Densityof water = ` rho = 1000 KG //m^(-3)` `"" P_1= h_1dg, h_1= 0.010 m` Density of mercury `= d= 13.6 XX 10 ^(-3)= 13600 kg//m^(-3)` `""P_2 = h_2dg` ` (h_1dg)/(rho )+(1)/(2) v_1^(2)= (h_2dg)/(rho)+(1)/(2) v_2^(2)` ` ""h_2 =h_1 +(rho)/(2dg)(v_1^(2) -v_2^(2)) ` ` ""= 0.010 +(10^(3))/( 2xx 13600 xx 9.8) (0.24^(2)- 0.48 ^(2))` ` "" =0.010 - 0.000648` ` "" = 0.0094` m