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Water jet issues water from a nozzle of `2 cm^(2)` cross-section with velocity 30 cm/s and strikes a plane surface placed at right angles to the jet. The force exerted on the plane isA. 200 dyneB. 400 dyneC. 1800 dyneD. None of the above |
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Answer» Correct Answer - C `thereforeF=(Deltap)/(Deltat)=v(Deltam)/(Deltat)=rhoAv(Deltax)/(Deltat)` `=rhoAv((vDeltat)/(Deltat))=1xx2xx(30)^(2)=1800` dyne |
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