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Wave equation for one progressive harmonic wave isy = 10 ^(-4) sin (600 t - 2x + (pi)/(3))m and t is in s). Velocity of the wave would be ...... m/s |
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Answer» 300 `y = 10 ^(-4) SIN (600 t - 2x + (pi)/(t))` with `y = a sin (omega t - kx +phi)` we get, `omega = 600 rad//s` `K = 2 rad //m` `therefore v = (omega )/(k) = (600)/(2) = 300 (m)/(s)` |
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