1.

Wavelength of different ra diations are given below. `lambda` (A) ` = 300nmlambda` (B) =300 `mumlambda` (C) `=3nmlambda` (D)=`30overset(@)A` Arrange these radiations in the increasing order of their energies.

Answer» `lambda`(A)`=300nm=300xx10^(-9)m,lambda` (B) `=300mum=300xx10^(-6)m`
`lambda` (C)=`3nm=3xx10^(-9) m lambda` (D) `= 30overset(@)A= 30xx10^(-10)m=3xx10^(-9)m`
Energy `E=(hc)/(lambda)`
Therefore `E=(1)/(lambda)`
increasing order of energy is `BltAltC=D`


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