Wavelengths of different rad iatio n s are given below : lambda(A) - 300 nm lambda(B) = 300 mum lambda(C) = 3 nm lambda(D) = 30A Arrange the seradiations in th eincreasing order of their energies.

Wavelengths of different rad iatio n s are given below : lambda(A) - 3

1.	Wavelengths of different rad iatio n s are given below : lambda(A) - 300 nm lambda(B) = 300 mum lambda(C) = 3 nm lambda(D) = 30A Arrange the seradiations in th eincreasing order of their energies.
Answer» SOLUTION :`LAMBDA(A) = 300 nm = 300 xx 10^(-9)` m `lambda(B) = 300 mu m = 300 xx 10^(-6)m` `lambda (C) = 3nm = 3 xx 10^(-9) m` `lambda(D) = 30A = 30 xx I10^(-10) m = 3 xx 10^(-9) m` he 1 Energy, `E = (hc)/(lambda)`So, `E prop (1)/(lambda)` -INCREASING order of energy is `B lt A lt C = D`