Wavelengths of different radiations are given below : lamda (A) = 300nm, lamda (B) = 300mu m, lamda(C) = 3nm, lamda(D) = 30 Å Arrange these radiations in the increasing order of their energies.

Wavelengths of different radiations are given below : lamda (A) = 300

1.	Wavelengths of different radiations are given below : lamda (A) = 300nm, lamda (B) = 300mu m, lamda(C) = 3nm, lamda(D) = 30 Å Arrange these radiations in the increasing order of their energies.
Answer» SOLUTION :`lamda (A) = 300NM = 300 xx 10^(-9) m = 3 xx 10^(-7) m, lamda (B) = 300 mu m = 300 xx 10^(-6) m = 3 xx 10^(-4) m lamda (C) = 3nm 3 xx 10^(-9)m, lamda (D) = 30 Å = 30 xx 10^(-10) m = 3 xx 10^(-9) m` `E = hv = h (c)/(lamda)`. THUS, `E prop (1)/(lamda)`. Hence, increasing order of energy is `B lt A lt C = D`