InterviewSolution
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InterviewSolution
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Wavelengths of different radiations are given below: (A) 300nm (B) `300 mu m` (C) 3nm (`30A^(@)` Arrange these radiations in the increasing order of their energies. |
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Answer» Let us convert the different radiations in the same units i.e. metre (m) `lambda(A) =300 nm = 300 xx10^(-9)=3xx10^(-7)m` `lambda (B) = 300 mu m = 300xx10^(-6) = 3xx10^(-4)m` `lambda(C)=3 nm = 3xx10^(-9) = 3xx10^(-9)m` `lambda(D) = 30 Ã… = 30 xx 10^(-10)=3xx10^(-9)m`. Energy (E) and wavelength `(lambda)` are related to each other as E `pro 1//lambda`. Thus , greater the wavelength of a radiation, lesser is its energy. ln the light of this, the increasing order of energies is : `B lt A lt C=D` |
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