We have 1.6 g CH_(4),1.7gNH_(3)and1.8gH_(2)O select correct the altern

1.	We have 1.6 g CH_(4),1.7gNH_(3)and1.8gH_(2)O select correct the alternate(s).
Answer» There are equal number of moles of each reactant Total number of ATOMS in `CH_(4)gtNH_(3)gtH_(2)O` Total number of H-atoms are in the ratio of `4:3:2` Total number of C-atoms in `CH_(4)lt` that of N-atoms in `NH_(3)lt` that of O-atoms in `H_(2)O` Solution :moles = `(1.6)/(10),(1.7)/(17),(1.8)/(18)` atoms = `0.1N_(0)xx5,0.1N_(0)xx4,0.1N_(0)xx3` H-atoms = `0.1N_(0)xx4,0.1N_(0)xx3,0.1N_(0)xx2` no. of `C=N=O`

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