InterviewSolution
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InterviewSolution
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We have taken a saturated solution of `AgBr`, whose `K_(sp)` is `12xx10^(-14).` If `10^(-7)M` of `AgNO_(3)` are added to `1L` of this solutino, find the conductivity `(` specific conductance `)` of the solution in terms of `10^(-7)S m^(-1)` units. Given `:` `lambda^(@)._((Ag^(o+)))=6xx10^(-3)S m^(2) mol^(-1)` `lambda^(@)._((Br^(c-)))=8xx10^(-3)S m^(2)mol^(-1)` `lambda^(@)._((NO_(3)^(C-)))=7XX10^(-3)S m^(2) mol^(-1)` |
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Answer» Solubility of `AgBr` in presence of `10^(-07)` mole of `AgNO_(3)` solution `K_(SP_(AgBr)) = [Ag^(+)][Br^(-)]` `12 xx 10^(-14) = [S + 10^(-7)] xx S` `:. S = 3 xx 10^(-7)M` `:. [Ag^(+)] = [3 xx 10^(-7) + 10^(-7)] = 4 xx 10^(-7) M` `[Br^(-)] = 3 xx 10^(-7) M` `[NO_(3)^(-)] = 3 xx 10^(-7)M` `because kappa = (lambda^(@) xx M)/(1000)` (`lambda` in `S m^(2) mol^(-1) = lambda xx 10^(4) s cm^(2) mol^(-1)`) `:. kappa_(Ag^(+)) = (6 xx 10^(-3) xx 10^(4) xx 4 xx 10^(-7))/(1000)` `= 24 xx 10^(-9) S cm^(-1)` `kappa_(Br^(-)) = (8 xx 10^(-3) xx 10^(4) xx 3 xx 10^(-7))/(1000)` `= 24 xx 10^(-9) S cm^(-1)` `kappa_(NO_(3)^(-)) = (7 xx 10^(-3) xx 10^(4) xx 10^(-7))/(1000)` `= 7 xx 10^(-9) S cm^(-1)` `:. kappa_("total") = kappa_(Ag^(+)) + kappa_(Br^(-)) + kappa_(NO_(3)^(-))` `= 24 xx 10^(-9) + 24 xx 10^(-9) + 7 xx 10^(-9)` `= 55 xx 10^(-9) S cm^(-1) = 55 xx 10^(-7) S cm^(-1)` in the unit of `1 xx 10^(-7) Sm^(-1)`, the conductivity is `55`. |
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