We know that If a ball of mass 1 kg is kept at a height 10 m possesses

1.	We know that If a ball of mass 1 kg is kept at a height 10 m possesses potential energy 'mgh' i.e. (1×10×10)=100 J. (Take earth surface as the reference, where m = mass of the object, g = acceleration due to gravity, h = height of the object from the earth's surface) What will be the kinetic energy of the ball when the ball is allowed to freely fall from a height 10m from the surface of the earth and hits the ground? (Take g=10ms2 and neglect air drag)
Answer» We know that If a ball of mass 1 kg is kept at a height 10 m possesses potential energy 'mgh' i.e. $(1 \times 10 \times 10) = 100$ J. (Take earth surface as the reference, where m = mass of the object, g = acceleration due to gravity, h = height of the object from the earth's surface) What will be the kinetic energy of the ball when the ball is allowed to freely fall from a height 10m from the surface of the earth and hits the ground? (Take $g = 10 \frac{m}{s^{2}}$ and neglect air drag)

We know that If a ball of mass 1 kg is kept at a height 10 m possesses potential energy 'mgh' i.e. (1×10×10)=100 J. (Take earth surface as the reference, where m = mass of the object, g = acceleration due to gravity, h = height of the object from the earth's surface) What will be the kinetic energy of the ball when the ball is allowed to freely fall from a height 10m from the surface of the earth and hits the ground? (Take g=10ms2 and neglect air drag)

Answer»

We know that If a ball of mass 1 kg is kept at a height 10 m possesses potential energy 'mgh' i.e. $(1 \times 10 \times 10) = 100$ J.

(Take earth surface as the reference, where m = mass of the object, g = acceleration due to gravity, h = height of the object from the earth's surface)
What will be the kinetic energy of the ball when the ball is allowed to freely fall from a height 10m from the surface of the earth and hits the ground?
(Take $g = 10 \frac{m}{s^{2}}$ and neglect air drag)

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