1.

Weak Acid HA K_a is 1.0 xx 10^(-5) in 1 litre 0.100 mole Acid is solubic. At equilibrium dissociation is …….

Answer»

`1.00%`
`99.0%`
`0.100%`
`99.9%`

SOLUTION :In ATOM solution of HP
`{:(,HA_((aq))+ H_2O_((L)) hArr, H_3O_((aq))^(+) + , A_((aq))^(-)),("At equilibrium",(1-x)M, xM,xM):}`
`K_a=[H_3O^+]^2/((1-x)) approx [H_3O^+]^2/C^0`
`therefore [H_3O^+]=SQRT(K_axxC^0)=sqrt(1.0xx10^(-5)xx0.1)`
`=1.0xx10^(-3)` M
% of ionization = `(1.0xx10^(-3))xx100` = 0.1


Discussion

No Comment Found