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Weak Acid HA K_a is 1.0 xx 10^(-5) in 1 litre 0.100 mole Acid is solubic. At equilibrium dissociation is ……. |
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Answer» `1.00%` `{:(,HA_((aq))+ H_2O_((L)) hArr, H_3O_((aq))^(+) + , A_((aq))^(-)),("At equilibrium",(1-x)M, xM,xM):}` `K_a=[H_3O^+]^2/((1-x)) approx [H_3O^+]^2/C^0` `therefore [H_3O^+]=SQRT(K_axxC^0)=sqrt(1.0xx10^(-5)xx0.1)` `=1.0xx10^(-3)` M % of ionization = `(1.0xx10^(-3))xx100` = 0.1 |
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