Weak acids and bases are not completely ionised when dissolved in polar medium like water H rarr H^(+) +A^(-) {:(t_(0),C,O,O),(t_(eq),C-Calpha,Calpha,Calpha):} K_(a)=(Calpha^(2))/(1-aplha)=Calpha^(2),alphasqrt((K_(a))/(C)) :. (alpha_(1))/(alpha_(2))=sqrt((Ka_(1))/(Ka_(2))),(alpha_(1))/(alpha_(2))=sqrt((C_(2))/(C_(1))) ( For two acids at same conc.) (for same acid at diff conc. ) Relative strength of two weak monoprotic acids may be given as

Weak acids and bases are not completely ionised when dissolved in pola

1.	Weak acids and bases are not completely ionised when dissolved in polar medium like water H rarr H^(+) +A^(-) {:(t_(0),C,O,O),(t_(eq),C-Calpha,Calpha,Calpha):} K_(a)=(Calpha^(2))/(1-aplha)=Calpha^(2),alphasqrt((K_(a))/(C)) :. (alpha_(1))/(alpha_(2))=sqrt((Ka_(1))/(Ka_(2))),(alpha_(1))/(alpha_(2))=sqrt((C_(2))/(C_(1))) ( For two acids at same conc.) (for same acid at diff conc. ) Relative strength of two weak monoprotic acids may be given as
Answer» ` ([H^(+)])/([H^(+)]_2) ` `(alpha _1)/(alpha_2) ` `SQRT((Ka1)/(Ka_2))` All of the above SOLUTION :Relative strength` = ([H^(+)])/([H^(+)]_2) = (sqrt(K_(a_1)))/(sqrt(K_(a_2)))=(alpha _1)/(alpha_2)`