Weak acids and bases are not completely ionised when dissolved in polar medium like water H rarr H^(+) +A^(-) {:(t_(0),C,O,O),(t_(eq),C-Calpha,Calpha,Calpha):} K_(a)=(Calpha^(2))/(1-alpha)=Calpha^(2),alphasqrt((K_(a))/(C)) :. (alpha_(1))/(alpha_(2))=sqrt((Ka_(1))/(Ka_(2))),(alpha_(1))/(alpha_(2))=sqrt((C_(2))/(C_(1))) ( For two acids at same conc.) (for same acid at diff conc. ) 0.01M CH_(3),COOH is 4.24% ionised. What will be the pereentage ionisation of 0.1 M CH_(3),COOH.

Weak acids and bases are not completely ionised when dissolved in pola

1.	Weak acids and bases are not completely ionised when dissolved in polar medium like water H rarr H^(+) +A^(-) {:(t_(0),C,O,O),(t_(eq),C-Calpha,Calpha,Calpha):} K_(a)=(Calpha^(2))/(1-alpha)=Calpha^(2),alphasqrt((K_(a))/(C)) :. (alpha_(1))/(alpha_(2))=sqrt((Ka_(1))/(Ka_(2))),(alpha_(1))/(alpha_(2))=sqrt((C_(2))/(C_(1))) ( For two acids at same conc.) (for same acid at diff conc. ) 0.01M CH_(3),COOH is 4.24% ionised. What will be the pereentage ionisation of 0.1 M CH_(3),COOH.
Answer» `1.33%` ` 4.24% ` ` 5.24% ` ` 0.33%` Solution : ` (alpha_1)/(alpha_2) =SQRT((C_2)/(C_1)), (4.24)/(alpha_2)= sqrt((10^(-1))/(10^(-2)))` ` (18)/(alpha_2^(2))=10 , alpha_2^(2)= 1.8 rArr ALPHA =sqrt(1.8)=1.34%`