`wedge_(m)^(0)H_(2)O` is equal to____A. `wedge_(m(HCl))^(0)+wedge_(m(NaOH))^(0)-wedge_(m(NaCl))^(0)`B. `wedge_(m(HNO_(3)))^(0)+wedge_(m(NaNO_(3)))^(0)-wedge_(m(NaOH))^(0)`C. `wedge_((HNO_(3)))^(0)+wedge_(m(NaOH))^(0)-wedge_(m(NaOH_(3)))^(0)`D. `wedge_(m(NH_(4)OH))^(0)+wedge_(m(HCl))^(0)-wedge_(m(NH_(4)Cl))^(0)`

`wedge_(m)^(0)H_(2)O` is equal to____A. `wedge_(m(HCl))^(0)+wedge_(m(N

1.	`wedge_(m)^(0)H_(2)O` is equal to____A. `wedge_(m(HCl))^(0)+wedge_(m(NaOH))^(0)-wedge_(m(NaCl))^(0)`B. `wedge_(m(HNO_(3)))^(0)+wedge_(m(NaNO_(3)))^(0)-wedge_(m(NaOH))^(0)`C. `wedge_((HNO_(3)))^(0)+wedge_(m(NaOH))^(0)-wedge_(m(NaOH_(3)))^(0)`D. `wedge_(m(NH_(4)OH))^(0)+wedge_(m(HCl))^(0)-wedge_(m(NH_(4)Cl))^(0)`
Answer» Correct Answer - A::D `wedge_(m(H_(2)O))^(@)=lamda_(H^(+))^(@)+lamda_(OH^(-))^(@)`. We get this expressions from (a) and (d).

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