`wedge^(@)._(m)` of `BaCl_(2) , H_(2)SO_(4)`, and `HCl(aq)` solutions are `x_(1),x_(2),` and `x_(3)` respectively. `wedge_(m(BaSO_(4)))` is `:`A. `x_(1)+x_(2)-x_(3)`B. `x_(1)-x_(2)-x_(3)`C. `x_(1)+x_(2)-2x_(3)`D. `x_(1)-2x_(2)+x_(3)`

`wedge^(@)._(m)` of `BaCl_(2) , H_(2)SO_(4)`, and `HCl(aq)` solutions

1.	`wedge^(@)._(m)` of `BaCl_(2) , H_(2)SO_(4)`, and `HCl(aq)` solutions are `x_(1),x_(2),` and `x_(3)` respectively. `wedge_(m(BaSO_(4)))` is `:`A. `x_(1)+x_(2)-x_(3)`B. `x_(1)-x_(2)-x_(3)`C. `x_(1)+x_(2)-2x_(3)`D. `x_(1)-2x_(2)+x_(3)`
Answer» Correct Answer - C `wedge^(@)._(m(BaCl_(2)))=lambda_(m)^(@)._((Ba^(2+)))+2lambda^(@)._(m(Cl^(c-)))` `wedge^(@)._(m(H_(2)SO_(4)))=2lambda^(@)._(m(H^(o+)))+lambda^(@)._(m(SO_(4)^(2-)))` `wedge^(@)._(m(HCl))=wedge^(@)._(m(BaCl_(2)))-2wedge^(@)._(m(HCl))` `x_(1)+x_(2)-2x_(3)`

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`wedge^(@)._(m)` of `BaCl_(2) , H_(2)SO_(4)`, and `HCl(aq)` solutions are `x_(1),x_(2),` and `x_(3)` respectively. `wedge_(m(BaSO_(4)))` is `:`A. `x_(1)+x_(2)-x_(3)`B. `x_(1)-x_(2)-x_(3)`C. `x_(1)+x_(2)-2x_(3)`D. `x_(1)-2x_(2)+x_(3)`

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