Weight of CO2 in a 10L cylinder at 5atm and 27degree

1.	Weight of CO2 in a 10L cylinder at 5atm and 27degree
Answer» ANSWER: $PV=nRT=MmRTP=5 atm,V=10 L,T=300 K,R=0.0821 L atm K−1mol−1m=RTPVM=0.0821×3005×10×44=89.3 g.$ EXPLANATION: *HOPE* it *HELPED* *you* *friend* if it *helps* *you* *mark* it as *brainliest*

Answer»

$PV=nRT=MmRTP=5 atm,V=10 L,T=300 K,R=0.0821 L atm K−1mol−1m=RTPVM=0.0821×3005×10×44=89.3 g.$