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Weight of copper oxide obtained by heating `2.16 g` of metallic copper with `HNO_(3)` and subsequent ingnition was `2.70 g` In another experient, `1.15 g` of copper oxide on reduction yielded `0.92 g` of copper. Show that the results illustrance the law of definite proportions. |
Answer» Case I : `underset((2.16 g))(Cu) + HNO_(3) rarr Cu(NO_(3))_(2) overset(Delta)rarr underset(2.7 g)(CuO)` Weight of oxygen `= 2.7 - 2.16 = 0.54 g` % of `O_(2)` in `CuO = (0.54 xx 100)/(2.7) = 20%` case II : Copper oxide taken `= 1.15 g` Copper left `= 0.92 g` oxygen present `= 1.15 - 0.92 = 0.23 g` % of `O_(2)` in `CuO = (0.23 xx 100)/(1.15) = 20%` |
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