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What a volume of oxygen gas measured at s.t.p will be produced during electrolysis by current of 5a supplied for 30 minutes |
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Answer» Current, I=1A Time, t=16 min 5 sec= 965 seconds n=2 Cu +2 +2e − ⟶Cu 4OH −1 ⟶O 2
+2H 2
O+4e −1
W= nF I×t×M
⇒W= 2×96500 1×965×63.5
⇒W=0.3175g 2×63.5g⟶22.4 litreO 2
⇒0.3175g⟶ 63.5×2 0.3175
×22.4 |
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