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What amount of dioxygen (in gram) contains 1.8 x 1022 molecules?(A) 0.0960 (B) 0.960 (C) 9.60 (D) 96.0 |
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Answer» Correct option: (B) 0.960 6.022 x 1023 dioxygen molecules are present in 1 mole i.e., 32 g of dioxygen. ∴ 1.8 x 1022 dioxygen molecules will be present in \(\cfrac{1.8\, \times\,10^{22}\,\times\,32}{6.022 \,\times\,10^{23}}\) = 0.96 g of dioxygen. |
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