1.

What amount of heat is liberated during the formation of one gram of `He^(4)` from deuterium `H^(2)`? What mess of coal with calorific value of `30kJ//g` is thermally equivalent to the magnitude obrained?

Answer» The reaction is (in effect).
`H^(2)+H^(2) rarrHe^(4)+Q`
Then `Q=2 Delta_(H)^(2)-Delta_(He^(4))+Q`
`=0.02820-0.00260`
`=0.02560amu=23MeV`
Hence the energy realeased in `1 gm`of `He^(4)` is
`(6.023xx10^(23))/(4)xx23.8xx16.03xx10^(-13)Jou l e=5.75xx10^(8)kJ`
This energy can be derived from
`(5.75xx10^(8))/(30000)kg= 1.9xx10^(4)`kg of Coal.


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