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What amount of heat will be generated in a coil of resistance `R` due to a charge q passing through it if the current in the coil a. decreases down to zero uniformly during a time interval `t_0`? b. decrases down to zero having its value every `t_0` seconds?A. `(2q^(2)R)/(3Deltat)`B. `(3q^(2)R)/(2Deltat)`C. `(4q^(2)R)/(3Deltat)`D. `(3q^(2)R)/(4Deltat)` |
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Answer» Correct Answer - C As current I is function of time and at `t=0` and `Deltat`, it equal `i_(0)` and zero respectively it may be represented as, `i=i_(0)(1-(t)/(Deltat))` Thus `q=int_(0)^(Deltat)idt=int_(0)^(Deltat)i_(0)(1-(t)/(Deltat))dt=(i_(0)Deltat)/(2)` so, `i_(0)=(2q)/(Deltat)` The heat generated `H=int_(0)^(Deltat)i^(2)Rdt=int_(0)^(Deltat)[(2q)/(Deltat)(1-(t)/(Deltat))]^(2)Rdt=(4q^(2)R)/(3Deltat)` |
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