1.

What amount of urea dissolved in 1 kg water at constanttemperature ,so that vapour pressure of the solution reduced by 2% ? ( MV of urea= 60 gm // mole)

Answer»

<P>68 gm
60gm
50 gm
75 gm

Solution : `Delta P= ( 2P^(0))/( 100)`
`:. (Delta P)/( P^(0)) =(1)/(50) =X ` ( mole fraction of urea )
`= ( m )/( 55.55 + m ) `
`:. M= 1.134 ` ( malality of urea )
`:. `Mass of urea `( W_(2)) = 1.134 xx 60 = 68 gm`


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