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What are the dimensional formulae of `omega` and K in the relation `y=Asin(omegat-Kx)`?A. `[M^(0)L^(0)T^(2)][M^(0)L^(-1)T^(0)]`B. `[M^(0)L^(0)T^(-1)][M^(0)L^(-1)T^(0)]`C. `[M^(0)L^(0)T^(-1)][M^(0)L^(1)T^(0)]`D. `[M^(0)L^(0)T^(-1)][M^(0)L^(1)T^(-1)]` |
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Answer» Correct Answer - b The argument of any trignometrical function is an angle. `therefore (omegat-Kx)` is an angle `(theta)`. It has no dimensions. `therefore omegat` and Kx are dimensionless. `omegat` is dimensionless, if the dimension of `omega` `=(1)/(T)=T^(-1)` `therefore [omega]=[M^(0)L^(0)T^(-1)]` Similarly, Kx will be dimensionless, if the dimension of `K=(1)/(x)=(1)/(L)=L^(-1)` `therefore [K]=[M^(0)L^(-1)T^(0)]` |
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