What are the dimensions of mu_(0)epsilon_(0)? Here mu_(0)= magnetic permeability in vacuum, epsilon_(0)= electric permittivity in vacuum

What are the dimensions of mu_(0)epsilon_(0)? Here mu_(0)= magnetic p

1.	What are the dimensions of mu_(0)epsilon_(0)? Here mu_(0)= magnetic permeability in vacuum, epsilon_(0)= electric permittivity in vacuum
Answer» `[ML^(-2)T^(-2)]` `[L^(-2)T^(-2)]` `[L^(-2)T^(2)]` None of these Solution :(c) As we know the SPEED of LIGHT `c=1/(SQRT(mu_(0)epsilon_(0))` or `c^(2)=1/(mu_(0)epsilon_(0)) :. mu_(0)epsilon_(0)=1/(c^(2))=1/([LT^(-1)]^(2))=[L^(-2)T^(2)]`