InterviewSolution
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InterviewSolution
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What are the dimensions of Reynolds number ? |
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Answer» `R = (rhov_(0)D)/(eta)` `(rho` is density of the fluid `v_(0)` is the critical velocity, D is diameter through which the fluid is flowing and `eta` is the coefficient of viscosity of the fluid) `R([ML^(-3)][LT^(-1)][L])/([ML^(-1)T^(-1)])=[(ML^(-1)T^(-1))/(ML^(-1)T^(-1))]=[M^(0)L^(0)T^(0)]` `:. R` is dimensionless. |
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