1.

What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results? ul(C)H_(3)ul(C)OOH

Answer»

Solution :The average O.N. of C in `CH_(3)COOH` can be calculated as follows.
`overset(x+1)(CH_(3))overset(x-2)(CO)overset(-2+1)(OH)`
`(x)+[(+1)xx3]+(x)+[(-2)xx2]+(+1)=0`
or
Let us CONSIDER the STRUCTURE of `CH_(3)COOH`,
`H-underset(H)underset(|)overset(H)overset(|2)C-overset(O)overset(||1)C-O-H`
`C_(2)` is attached to three H atoms and one -COOH group (ON. = -1).
`:.` For this carbon,
`[(+1)xx3]+(x)+(-1)=0`
or x=-2
`C_(1)` is attached to one -OH group (O.N. = -1), one o atom (O.N. = -2) and one- `CH_(3)` group (O.N,=+1). Therefore, for `C_(1)`.
`(+1)+(x)+(-2)+(-1)=0`
or x=+2.


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