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What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results? ul(C)H_(3)ul(C)H_(2)OH |
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Answer» SOLUTION :The average oxidation number of C in `CH_(3)CH_(2)OH` can be CALCULATED as follows. `overset(x+1)(CH_(3))overset(x+1)(CH_(2))overset(-2)(O)overset(+1)H` `(x)+[(+1)xx3]+(x)+[(+1)xx2]+(-2)+(+1)=0` or `2x+3+2-2+1=0` or x=-2 Let us consider the structure of `CH_(3)CH_(2)OH` as GIVEN below `H-underset(H)underset(|)overset(H)overset(|2)S-underset(H)underset(|)overset(H)overset(|1)C-O-H` C ATOM labelled as (2) is attached to three H atoms which are less electronegative than C and one `CH_(2)OH` group (O. N. = -1) which is more electronegative than C. Therefore, for this carbon `(+1)+[(+1)xx2]+(x)+(-1)=0` x=-2. |
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