1.

What are the oxidation number of the underlined elements in each of the following and how do you rationalise your results? ul(C)H_(3)ul(C)H_(2)OH

Answer»

SOLUTION :The average oxidation number of C in `CH_(3)CH_(2)OH` can be CALCULATED as follows.
`overset(x+1)(CH_(3))overset(x+1)(CH_(2))overset(-2)(O)overset(+1)H`
`(x)+[(+1)xx3]+(x)+[(+1)xx2]+(-2)+(+1)=0`
or `2x+3+2-2+1=0`
or x=-2
Let us consider the structure of `CH_(3)CH_(2)OH` as GIVEN below
`H-underset(H)underset(|)overset(H)overset(|2)S-underset(H)underset(|)overset(H)overset(|1)C-O-H`
C ATOM labelled as (2) is attached to three H atoms which are less electronegative than C and one `CH_(2)OH` group (O. N. = -1) which is more electronegative than C. Therefore, for this carbon
`(+1)+[(+1)xx2]+(x)+(-1)=0`
x=-2.


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